Find Three Ordered Pair Solutions y+1=3(x-4)

$y + 1 = 3 (x - 4)$

Solve the equation for $y$ .

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Simplify $3 (x - 4)$ .

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Apply the distributive property.

$y + 1 = 3 x + 3 \cdot - 4$

Multiply $3$ by $- 4$ .

$y + 1 = 3 x - 12$

Move all terms not containing $y$ to the right side of the equation.

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Subtract $1$ from both sides of the equation.

$y = 3 x - 12 - 1$

Subtract $1$ from $- 12$ .

$y = 3 x - 13$

Choose any value for $x$ that is in the domain to plug into the equation.

Choose $0$ to substitute in for $x$ to find the ordered pair.

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Remove parentheses.

$y = 3 (0) - 13$

Simplify $3 (0) - 13$ .

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Multiply $3$ by $0$ .

$y = 0 - 13$

Subtract $13$ from $0$ .

$y = - 13$

Use the $x$ and $y$ values to form the ordered pair.

$(0, - 13)$

Choose $1$ to substitute in for $x$ to find the ordered pair.

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Remove parentheses.

$y = 3 (1) - 13$

Simplify $3 (1) - 13$ .

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Multiply $3$ by $1$ .

$y = 3 - 13$

Subtract $13$ from $3$ .

$y = - 10$

Use the $x$ and $y$ values to form the ordered pair.

$(1, - 10)$

Choose $2$ to substitute in for $x$ to find the ordered pair.

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Remove parentheses.

$y = 3 (2) - 13$

Simplify $3 (2) - 13$ .

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Multiply $3$ by $2$ .

$y = 6 - 13$

Subtract $13$ from $6$ .

$y = - 7$

Use the $x$ and $y$ values to form the ordered pair.

$(2, - 7)$

These are three possible solutions to the equation.

$(0, - 13), (1, - 10), (2, - 7)$

Find Three Ordered Pair Solutions y+1=3(x-4)

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