# Find Where Undefined/Discontinuous 1/(x-5)-3/(x+7)=12/(x^2+2x-35)

Move to the left side of the equation by subtracting it from both sides.
Set the denominator in equal to to find where the expression is undefined.
Add to both sides of the equation.
Set the denominator in equal to to find where the expression is undefined.
Subtract from both sides of the equation.
Set the denominator in equal to to find where the expression is undefined.
Solve for .
Factor using the AC method.
Consider the form . Find a pair of integers whose product is and whose sum is . In this case, whose product is and whose sum is .
Write the factored form using these integers.
If any individual factor on the left side of the equation is equal to , the entire expression will be equal to .
Set the first factor equal to and solve.
Set the first factor equal to .
Add to both sides of the equation.
Set the next factor equal to and solve.
Set the next factor equal to .
Subtract from both sides of the equation.
The final solution is all the values that make true.
The equation is undefined where the denominator equals , the argument of a square root is less than , or the argument of a logarithm is less than or equal to .
Find Where Undefined/Discontinuous 1/(x-5)-3/(x+7)=12/(x^2+2x-35)