# Find Where Undefined/Discontinuous 5/(x+4)-2/(x-4)=(5x)/(x^2-16) Move to the left side of the equation by subtracting it from both sides.
Set the denominator in equal to to find where the expression is undefined.
Subtract from both sides of the equation.
Set the denominator in equal to to find where the expression is undefined.
Add to both sides of the equation.
Set the denominator in equal to to find where the expression is undefined.
Solve for .
Add to both sides of the equation.
Take the square root of both sides of the equation to eliminate the exponent on the left side.
The complete solution is the result of both the positive and negative portions of the solution.
Simplify the right side of the equation.
Rewrite as .
Pull terms out from under the radical, assuming positive real numbers.
The complete solution is the result of both the positive and negative portions of the solution.
First, use the positive value of the to find the first solution.
Next, use the negative value of the to find the second solution.
The complete solution is the result of both the positive and negative portions of the solution.
The equation is undefined where the denominator equals , the argument of a square root is less than , or the argument of a logarithm is less than or equal to .
Find Where Undefined/Discontinuous 5/(x+4)-2/(x-4)=(5x)/(x^2-16)     