# Find Where Undefined/Discontinuous ( square root of 30(x-1))÷( square root of 5x^2) Set the denominator in equal to to find where the expression is undefined.
Solve for .
To remove the radical on the left side of the equation, square both sides of the equation.
Simplify each side of the equation.
Multiply the exponents in .
Apply the power rule and multiply exponents, .
Cancel the common factor of .
Cancel the common factor.
Rewrite the expression.
Simplify.
Raising to any positive power yields .
Solve for .
Divide each term by and simplify.
Divide each term in by .
Cancel the common factor of .
Cancel the common factor.
Divide by .
Divide by .
Take the square root of both sides of the equation to eliminate the exponent on the left side.
The complete solution is the result of both the positive and negative portions of the solution.
Simplify the right side of the equation.
Rewrite as .
Pull terms out from under the radical, assuming positive real numbers.
is equal to .
Verify each of the solutions by substituting them into and solving.
Set the radicand in less than to find where the expression is undefined.
Solve for .
Divide each term by and simplify.
Divide each term in by .
Cancel the common factor of .
Cancel the common factor.
Divide by .
Divide by .
Add to both sides of the inequality.
Set the radicand in less than to find where the expression is undefined.
Solve for .
Divide each term by and simplify.
Divide each term in by .
Cancel the common factor of .
Cancel the common factor.
Divide by .
Divide by .
Take the square root of both sides of the inequality to eliminate the exponent on the left side.
The complete solution is the result of both the positive and negative portions of the solution.
Simplify the right side of the equation.
Rewrite as .
Pull terms out from under the radical, assuming positive real numbers.
The complete solution is the result of both the positive and negative portions of the solution.
First, use the positive value of the to find the first solution.
Next, use the negative value of the to find the second solution. Since this is an inequality, flip the direction of the inequality sign on the portion of the solution.
The complete solution is the result of both the positive and negative portions of the solution.
and
This inequality has no solution.
No solution
No solution
No solution
No solution
The equation is undefined where the denominator equals , the argument of a square root is less than , or the argument of a logarithm is less than or equal to .
Inequality Form:
Interval Notation:
Find Where Undefined/Discontinuous ( square root of 30(x-1))÷( square root of 5x^2)     