Find Where Undefined/Discontinuous (x^2-4x+4)/(5x-10)

$\frac{x^{2} - 4 x + 4}{5 x - 10}$

Set the denominator in $\frac{x^{2} - 4 x + 4}{5 x - 10}$ equal to $0$ to find where the expression is undefined.

$5 x - 10 = 0$

Solve for $x$ .

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Add $10$ to both sides of the equation.

$5 x = 10$

Divide each term by $5$ and simplify.

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Divide each term in $5 x = 10$ by $5$ .

$\frac{5 x}{5} = \frac{10}{5}$

Cancel the common factor of $5$ .

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Cancel the common factor.

$\frac{5 x}{5} = \frac{10}{5}$

Divide $x$ by $1$ .

$x = \frac{10}{5}$

Divide $10$ by $5$ .

$x = 2$

The equation is undefined where the denominator equals $0$ , the argument of a square root is less than $0$ , or the argument of a logarithm is less than or equal to $0$ .

$x = 2$

Find Where Undefined/Discontinuous (x^2-4x+4)/(5x-10)

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