Graph 0.3x+0.4y>0.4

Math
0.3x+0.4y>0.4
Solve for y.
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Subtract 0.3x from both sides of the inequality.
0.4y>0.4-0.3x
Divide each term by 0.4 and simplify.
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Divide each term in 0.4y>0.4-0.3x by 0.4.
0.4y0.4>0.40.4+-0.3×0.4
Cancel the common factor of 0.4.
y>0.40.4+-0.3×0.4
Simplify each term.
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Divide 0.4 by 0.4.
y>1+-0.3×0.4
Move the negative in front of the fraction.
y>1-(0.3)x0.4
Factor 0.3 out of 0.3x.
y>1-0.3(x)0.4
Factor 0.4 out of 0.4.
y>1-0.3(x)0.4(1)
Separate fractions.
y>1-(0.30.4⋅x1)
Divide 0.3 by 0.4.
y>1-(0.75×1)
Divide x by 1.
y>1-(0.75x)
Multiply 0.75 by -1.
y>1-0.75x
y>1-0.75x
y>1-0.75x
y>1-0.75x
Find the slope and the y-intercept for the boundary line.
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Rewrite in slope-intercept form.
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The slope-intercept form is y=mx+b, where m is the slope and b is the y-intercept.
y=mx+b
Reorder 1 and -0.75x.
y>-0.75x+1
y>-0.75x+1
Use the slope-intercept form to find the slope and y-intercept.
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Find the values of m and b using the form y=mx+b.
m=-0.75
b=1
The slope of the line is the value of m, and the y-intercept is the value of b.
Slope: -0.75
y-intercept: 1
Slope: -0.75
y-intercept: 1
Slope: -0.75
y-intercept: 1
Graph a dashed line, then shade the area above the boundary line since y is greater than 1-0.75x.
y>1-0.75x
1-0.75x","isGrey":false,"dashed":false,"holes":[]}],"asymptotes":[],"segments":[],"areaBetweenCurves":[],"points":[],"HasGraphInput":true}” class=”GraphWrapper”>
Graph 0.3x+0.4y>0.4

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