Graph f(x)=[x] - MathMaster

$f (x) = [x]$

Rewrite the function as an equation.

$y = x$

Remove parentheses.

$y = x$

Use the slope-intercept form to find the slope and y-intercept.

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The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = 1$

$b = 0$

The slope of the line is the value of $m$ , and the y-intercept is the value of $b$ .

Slope: $1$

y-intercept: $(0, 0)$

Slope: $1$

y-intercept: $(0, 0)$

Any line can be graphed using two points. Select two $x$ values, and plug them into the equation to find the corresponding $y$ values.

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Find the x-intercept.

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To find the x-intercept(s), substitute in $0$ for $y$ and solve for $x$ .

$0 = x$

Rewrite the equation as $x = 0$ .

$x = 0$

x-intercept(s) in point form.

x-intercept(s): $(0, 0)$

Find the y-intercept.

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To find the y-intercept(s), substitute in $0$ for $x$ and solve for $y$ .

$y = 0$

Remove parentheses.

$y = 0$

y-intercept(s) in point form.

y-intercept(s): $(0, 0)$

Choose $1$ to substitute in for $x$ to find the ordered pair.

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Replace the variable $x$ with $1$ in the expression.

$f (1) = 1$

Simplify the result.

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Remove parentheses.

$f (1) = 1$

The final answer is $1$ .

$1$

The $y$ value at $x = 1$ is $1$ .

$y = 1$

Create a table of the $x$ and $y$ values.

$\begin{array}{c} x & y \\ 0 & 0 \\ 1 & 1 \end{array}$

Graph the line using the slope and the y-intercept, or the points.

Slope: $1$

y-intercept: $(0, 0)$

$\begin{array}{c} x & y \\ 0 & 0 \\ 1 & 1 \end{array}$

Graph f(x)=[x]

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