y+3=12⋅(x+2)

Subtract 3 from both sides of the equation.

y=x2+1-3

Subtract 3 from 1.

y=x2-2

y=x2-2

The slope-intercept form is y=mx+b, where m is the slope and b is the y-intercept.

y=mx+b

Find the values of m and b using the form y=mx+b.

m=12

b=-2

The slope of the line is the value of m, and the y-intercept is the value of b.

Slope: 12

y-intercept: -2

Slope: 12

y-intercept: -2

Choose 0 to substitute in for x to find the ordered pair.

Replace the variable x with 0 in the expression.

f(0)=02-2

Simplify the result.

Divide 0 by 2.

f(0)=0-2

Subtract 2 from 0.

f(0)=-2

The final answer is -2.

-2

-2

The y value at x=0 is -2.

y=-2

y=-2

Choose 2 to substitute in for x to find the ordered pair.

Replace the variable x with 2 in the expression.

f(2)=22-2

Simplify the result.

Divide 2 by 2.

f(2)=1-2

Subtract 2 from 1.

f(2)=-1

The final answer is -1.

-1

-1

The y value at x=2 is -1.

y=-1

y=-1

Create a table of the x and y values.

xy0-22-1

xy0-22-1

Graph the line using the slope and the y-intercept, or the points.

Slope: 12

y-intercept: -2

xy0-22-1

Graph y+3=1/2*(x+2)