y+3=12⋅(x+2)
Subtract 3 from both sides of the equation.
y=x2+1-3
Subtract 3 from 1.
y=x2-2
y=x2-2
The slope-intercept form is y=mx+b, where m is the slope and b is the y-intercept.
y=mx+b
Find the values of m and b using the form y=mx+b.
m=12
b=-2
The slope of the line is the value of m, and the y-intercept is the value of b.
Slope: 12
y-intercept: -2
Slope: 12
y-intercept: -2
Choose 0 to substitute in for x to find the ordered pair.
Replace the variable x with 0 in the expression.
f(0)=02-2
Simplify the result.
Divide 0 by 2.
f(0)=0-2
Subtract 2 from 0.
f(0)=-2
The final answer is -2.
-2
-2
The y value at x=0 is -2.
y=-2
y=-2
Choose 2 to substitute in for x to find the ordered pair.
Replace the variable x with 2 in the expression.
f(2)=22-2
Simplify the result.
Divide 2 by 2.
f(2)=1-2
Subtract 2 from 1.
f(2)=-1
The final answer is -1.
-1
-1
The y value at x=2 is -1.
y=-1
y=-1
Create a table of the x and y values.
xy0-22-1
xy0-22-1
Graph the line using the slope and the y-intercept, or the points.
Slope: 12
y-intercept: -2
xy0-22-1
Graph y+3=1/2*(x+2)
