Graph y>4/3x^2-12x+29

Math
y>43×2-12x+29
Combine 43 and x2.
y>4×23-12x+29
The equation is not linear, so the slope does not exist.
Not Linear
Graph a dashed line, then shade the area above the boundary line since y is greater than 4×23-12x+29.
y>4×23-12x+29
(4x^(2))/(3)-12x+29","isGrey":false,"dashed":false,"holes":[]}],"asymptotes":[],"segments":[],"areaBetweenCurves":[],"points":[],"HasGraphInput":true}” class=”GraphWrapper”>
Graph y>4/3x^2-12x+29

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