Reduce (x^(4b+1))/(x^(2-b))

$\frac{x^{4 b + 1}}{x^{2 - b}}$

Cancel the common factor of $x^{4 b + 1}$ and $x^{2 - b}$ .

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Factor $x^{2 - b}$ out of $x^{4 b + 1}$ .

$\frac{x^{2 - b} x^{4 b + 1 - (2 - b)}}{x^{2 - b}}$

Cancel the common factors.

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Multiply by $1$ .

$\frac{x^{2 - b} x^{4 b + 1 - (2 - b)}}{x^{2 - b} \cdot 1}$

Cancel the common factor.

$\frac{x^{2 - b} x^{4 b + 1 - (2 - b)}}{x^{2 - b} \cdot 1}$

Rewrite the expression.

$\frac{x^{4 b + 1 - (2 - b)}}{1}$

Divide $x^{4 b + 1 - (2 - b)}$ by $1$ .

$x^{4 b + 1 - (2 - b)}$

Simplify each term.

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Apply the distributive property.

$x^{4 b + 1 - 1 \cdot 2 - - b}$

Multiply $- 1$ by $2$ .

$x^{4 b + 1 - 2 - - b}$

Multiply $- - b$ .

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Multiply $- 1$ by $- 1$ .

$x^{4 b + 1 - 2 + 1 b}$

Multiply $b$ by $1$ .

$x^{4 b + 1 - 2 + b}$

Simplify by adding terms.

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Add $4 b$ and $b$ .

$x^{5 b + 1 - 2}$

Subtract $2$ from $1$ .

$x^{5 b - 1}$

Reduce (x^(4b+1))/(x^(2-b))

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