Rewrite in Exponential Form log base 1/2 of 16=-4

$\log_{\frac{1}{2}} (16) = - 4$

For logarithmic equations, $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ such that $x > 0$ , $b > 0$ , and $b \neq 1$ . In this case, $b = \frac{1}{2}$ , $x = 16$ , and $y = - 4$ .

$b = \frac{1}{2}$

$x = 16$

$y = - 4$

Substitute the values of $b$ , $x$ , and $y$ into the equation $b^{y} = x$ .

${(\frac{1}{2})}^{- 4} = 16$

Rewrite in Exponential Form log base 1/2 of 16=-4

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