Simplify/Condense log of 125+ log of 8

$\log (125) + \log (8)$

Use the product property of logarithms, $\log_{b} (x) + \log_{b} (y) = \log_{b} (x y)$ .

$\log (125 \cdot 8)$

Multiply $125$ by $8$ .

$\log (1000)$

Logarithm base $10$ of $1000$ is $3$ .

$3$

Simplify/Condense log of 125+ log of 8

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