Simplify (x^2-x-20)/(5-x)

Math
x2-x-205-x
Factor x2-x-20 using the AC method.
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Consider the form x2+bx+c. Find a pair of integers whose product is c and whose sum is b. In this case, whose product is -20 and whose sum is -1.
-5,4
Write the factored form using these integers.
(x-5)(x+4)5-x
(x-5)(x+4)5-x
Simplify terms.
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Cancel the common factor of x-5 and 5-x.
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Factor -1 out of x.
(-1(-x)-5)(x+4)5-x
Rewrite -5 as -1(5).
(-1(-x)-1(5))(x+4)5-x
Factor -1 out of -1(-x)-1(5).
-1(-x+5)(x+4)5-x
Reorder terms.
-1(-x+5)(x+4)-x+5
Cancel the common factor.
-1(-x+5)(x+4)-x+5
Divide -1(x+4) by 1.
-1(x+4)
-1(x+4)
Rewrite -1(x+4) as -(x+4).
-(x+4)
Apply the distributive property.
-x-1⋅4
Multiply -1 by 4.
-x-4
-x-4
Simplify (x^2-x-20)/(5-x)

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