x6+4×4-4x-1×3-1
Rewrite 1 as 13.
x6+4×4-4x-1×3-13
Since both terms are perfect cubes, factor using the difference of cubes formula, a3-b3=(a-b)(a2+ab+b2) where a=x and b=1.
x6+4×4-4x-1(x-1)(x2+x⋅1+12)
Multiply x by 1.
x6+4×4-4x-1(x-1)(x2+x+12)
One to any power is one.
x6+4×4-4x-1(x-1)(x2+x+1)
x6+4×4-4x-1(x-1)(x2+x+1)
Simplify (x^6+4x^4-4x-1)/(x^3-1)