Solve by Addition/Elimination 0.5m+0.7n=6.4 0.2m-0.7n=0.6

$0.5 m + 0.7 n = 6.4$ $0.2 m - 0.7 n = 0.6$

Add the two equations together to eliminate $n$ from the system.

Divide each term by $0.7$ and simplify.

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Divide each term in $0.7 m = 7$ by $0.7$ .

$\frac{0.7 m}{0.7} = \frac{7}{0.7}$

Cancel the common factor of $0.7$ .

$m = \frac{7}{0.7}$

Divide $7$ by $0.7$ .

$m = 10$

Substitute the value found for $m$ into one of the original equations, then solve for $n$ .

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Substitute the value found for $m$ into one of the original equations to solve for $n$ .

$0.5 (10) + 0.7 n = 6.4$

Multiply $0.5$ by $10$ .

$5 + 0.7 n = 6.4$

Move all terms not containing $n$ to the right side of the equation.

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Subtract $5$ from both sides of the equation.

$0.7 n = 6.4 - 5$

Subtract $5$ from $6.4$ .

$0.7 n = 1.4$

Divide each term by $0.7$ and simplify.

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Divide each term in $0.7 n = 1.4$ by $0.7$ .

$\frac{0.7 n}{0.7} = \frac{1.4}{0.7}$

Cancel the common factor of $0.7$ .

$n = \frac{1.4}{0.7}$

Divide $1.4$ by $0.7$ .

$n = 2$

This is the final solution to the independent system of equations.

$m = 10$

$n = 2$

Solve by Addition/Elimination 0.5m+0.7n=6.4 0.2m-0.7n=0.6

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