Solve by Graphing 3x-2y=0 , -3x-y=-18

$3 x - 2 y = 0$ , $- 3 x - y = - 18$

Subtract $3 x$ from both sides of the equation.

$- 2 y = - 3 x$

$- 3 x - y = - 18$

Divide each term by $- 2$ and simplify.

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Divide each term in $- 2 y = - 3 x$ by $- 2$ .

$\frac{- 2 y}{- 2} = \frac{- 3 x}{- 2}$

$- 3 x - y = - 18$

Cancel the common factor of $- 2$ .

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Cancel the common factor.

$\frac{- 2 y}{- 2} = \frac{- 3 x}{- 2}$

$- 3 x - y = - 18$

Divide $y$ by $1$ .

$y = \frac{- 3 x}{- 2}$

$- 3 x - y = - 18$

$y = \frac{- 3 x}{- 2}$

$- 3 x - y = - 18$

Dividing two negative values results in a positive value.

$y = \frac{3 x}{2}$

$- 3 x - y = - 18$

$y = \frac{3 x}{2}$

$- 3 x - y = - 18$

Add $3 x$ to both sides of the equation.

$y = \frac{3 x}{2}$

$- y = - 18 + 3 x$

Multiply each term in $- y = - 18 + 3 x$ by $- 1$

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Multiply each term in $- y = - 18 + 3 x$ by $- 1$ .

$y = \frac{3 x}{2}$

$(- y) \cdot - 1 = (- 18) \cdot - 1 + 3 x \cdot - 1$

Multiply $(- y) \cdot - 1$ .

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Multiply $- 1$ by $- 1$ .

$y = \frac{3 x}{2}$

$1 y = (- 18) \cdot - 1 + 3 x \cdot - 1$

Multiply $y$ by $1$ .

$y = \frac{3 x}{2}$

$y = (- 18) \cdot - 1 + 3 x \cdot - 1$

$y = \frac{3 x}{2}$

$y = (- 18) \cdot - 1 + 3 x \cdot - 1$

Simplify each term.

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Multiply $- 18$ by $- 1$ .

$y = \frac{3 x}{2}$

$y = 18 + 3 x \cdot - 1$

Multiply $- 1$ by $3$ .

$y = \frac{3 x}{2}$

$y = 18 - 3 x$

$y = \frac{3 x}{2}$

$y = 18 - 3 x$

$y = \frac{3 x}{2}$

$y = 18 - 3 x$

Create a graph to locate the intersection of the equations. The intersection of the system of equations is the solution.

$(4, 6)$

Solve by Graphing 3x-2y=0 , -3x-y=-18

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