Solve by Graphing x-2y=0 , x+2y=8

$x - 2 y = 0$ , $x + 2 y = 8$

Subtract $x$ from both sides of the equation.

$- 2 y = - x$

$x + 2 y = 8$

Divide each term by $- 2$ and simplify.

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Divide each term in $- 2 y = - x$ by $- 2$ .

$\frac{- 2 y}{- 2} = \frac{- x}{- 2}$

$x + 2 y = 8$

Cancel the common factor of $- 2$ .

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Cancel the common factor.

$\frac{- 2 y}{- 2} = \frac{- x}{- 2}$

$x + 2 y = 8$

Divide $y$ by $1$ .

$y = \frac{- x}{- 2}$

$x + 2 y = 8$

$y = \frac{- x}{- 2}$

$x + 2 y = 8$

Dividing two negative values results in a positive value.

$y = \frac{x}{2}$

$x + 2 y = 8$

$y = \frac{x}{2}$

$x + 2 y = 8$

Subtract $x$ from both sides of the equation.

$y = \frac{x}{2}$

$2 y = 8 - x$

Divide each term by $2$ and simplify.

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Divide each term in $2 y = 8 - x$ by $2$ .

$y = \frac{x}{2}$

$\frac{2 y}{2} = \frac{8}{2} + \frac{- x}{2}$

Cancel the common factor of $2$ .

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Cancel the common factor.

$y = \frac{x}{2}$

$\frac{2 y}{2} = \frac{8}{2} + \frac{- x}{2}$

Divide $y$ by $1$ .

$y = \frac{x}{2}$

$y = \frac{8}{2} + \frac{- x}{2}$

$y = \frac{x}{2}$

$y = \frac{8}{2} + \frac{- x}{2}$

Simplify each term.

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Divide $8$ by $2$ .

$y = \frac{x}{2}$

$y = 4 + \frac{- x}{2}$

Move the negative in front of the fraction.

$y = \frac{x}{2}$

$y = 4 - \frac{x}{2}$

$y = \frac{x}{2}$

$y = 4 - \frac{x}{2}$

$y = \frac{x}{2}$

$y = 4 - \frac{x}{2}$

Create a graph to locate the intersection of the equations. The intersection of the system of equations is the solution.

$(4, 2)$

Solve by Graphing x-2y=0 , x+2y=8

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