Solve by Graphing y=x^2-6x+8 2y+x=4

$y = x^{2} - 6 x + 8$ $2 y + x = 4$

Subtract $x$ from both sides of the equation.

$y = x^{2} - 6 x + 8$

$2 y = 4 - x$

Divide each term by $2$ and simplify.

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Divide each term in $2 y = 4 - x$ by $2$ .

$y = x^{2} - 6 x + 8$

$\frac{2 y}{2} = \frac{4}{2} + \frac{- x}{2}$

Cancel the common factor of $2$ .

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Cancel the common factor.

$y = x^{2} - 6 x + 8$

$\frac{2 y}{2} = \frac{4}{2} + \frac{- x}{2}$

Divide $y$ by $1$ .

$y = x^{2} - 6 x + 8$

$y = \frac{4}{2} + \frac{- x}{2}$

$y = x^{2} - 6 x + 8$

$y = \frac{4}{2} + \frac{- x}{2}$

Simplify each term.

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Divide $4$ by $2$ .

$y = x^{2} - 6 x + 8$

$y = 2 + \frac{- x}{2}$

Move the negative in front of the fraction.

$y = x^{2} - 6 x + 8$

$y = 2 - \frac{x}{2}$

$y = x^{2} - 6 x + 8$

$y = 2 - \frac{x}{2}$

$y = x^{2} - 6 x + 8$

$y = 2 - \frac{x}{2}$

Create a graph to locate the intersection of the equations. The intersection of the system of equations is the solution.

$(\frac{3}{2}, \frac{5}{4}), (4, 0)$

Solve by Graphing y=x^2-6x+8 2y+x=4

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