Solve by Substitution 3x+4y=4 , 6x+8y=8

$3 x + 4 y = 4$ , $6 x + 8 y = 8$

Solve for $x$ in the first equation.

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Subtract $4 y$ from both sides of the equation.

$3 x = 4 - 4 y$

$6 x + 8 y = 8$

Divide each term by $3$ and simplify.

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Divide each term in $3 x = 4 - 4 y$ by $3$ .

$\frac{3 x}{3} = \frac{4}{3} + \frac{- 4 y}{3}$

$6 x + 8 y = 8$

Cancel the common factor of $3$ .

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Cancel the common factor.

$\frac{3 x}{3} = \frac{4}{3} + \frac{- 4 y}{3}$

$6 x + 8 y = 8$

Divide $x$ by $1$ .

$x = \frac{4}{3} + \frac{- 4 y}{3}$

$6 x + 8 y = 8$

$x = \frac{4}{3} + \frac{- 4 y}{3}$

$6 x + 8 y = 8$

Move the negative in front of the fraction.

$x = \frac{4}{3} - \frac{4 y}{3}$

$6 x + 8 y = 8$

$x = \frac{4}{3} - \frac{4 y}{3}$

$6 x + 8 y = 8$

$x = \frac{4}{3} - \frac{4 y}{3}$

$6 x + 8 y = 8$

Replace all occurrences of $x$ with $\frac{4}{3} - \frac{4 y}{3}$ in each equation.

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Replace all occurrences of $x$ in $6 x + 8 y = 8$ with $\frac{4}{3} - \frac{4 y}{3}$ .

$6 (\frac{4}{3} - \frac{4 y}{3}) + 8 y = 8$

$x = \frac{4}{3} - \frac{4 y}{3}$

Simplify $6 (\frac{4}{3} - \frac{4 y}{3}) + 8 y$ .

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Simplify each term.

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Apply the distributive property.

$6 (\frac{4}{3}) + 6 (- \frac{4 y}{3}) + 8 y = 8$

$x = \frac{4}{3} - \frac{4 y}{3}$

Cancel the common factor of $3$ .

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Factor $3$ out of $6$ .

$3 (2) (\frac{4}{3}) + 6 (- \frac{4 y}{3}) + 8 y = 8$

$x = \frac{4}{3} - \frac{4 y}{3}$

Cancel the common factor.

$3 \cdot (2 (\frac{4}{3})) + 6 (- \frac{4 y}{3}) + 8 y = 8$

$x = \frac{4}{3} - \frac{4 y}{3}$

Rewrite the expression.

$2 \cdot 4 + 6 (- \frac{4 y}{3}) + 8 y = 8$

$x = \frac{4}{3} - \frac{4 y}{3}$

$2 \cdot 4 + 6 (- \frac{4 y}{3}) + 8 y = 8$

$x = \frac{4}{3} - \frac{4 y}{3}$

Multiply $2$ by $4$ .

$8 + 6 (- \frac{4 y}{3}) + 8 y = 8$

$x = \frac{4}{3} - \frac{4 y}{3}$

Cancel the common factor of $3$ .

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Move the leading negative in $- \frac{4 y}{3}$ into the numerator.

$8 + 6 (\frac{- 4 y}{3}) + 8 y = 8$

$x = \frac{4}{3} - \frac{4 y}{3}$

Factor $3$ out of $6$ .

$8 + 3 (2) (\frac{- 4 y}{3}) + 8 y = 8$

$x = \frac{4}{3} - \frac{4 y}{3}$

Cancel the common factor.

$8 + 3 \cdot (2 (\frac{- 4 y}{3})) + 8 y = 8$

$x = \frac{4}{3} - \frac{4 y}{3}$

Rewrite the expression.

$8 + 2 (- 4 y) + 8 y = 8$

$x = \frac{4}{3} - \frac{4 y}{3}$

$8 + 2 (- 4 y) + 8 y = 8$

$x = \frac{4}{3} - \frac{4 y}{3}$

Multiply $- 4$ by $2$ .

$8 - 8 y + 8 y = 8$

$x = \frac{4}{3} - \frac{4 y}{3}$

$8 - 8 y + 8 y = 8$

$x = \frac{4}{3} - \frac{4 y}{3}$

Combine the opposite terms in $8 - 8 y + 8 y$ .

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Add $- 8 y$ and $8 y$ .

$8 + 0 = 8$

$x = \frac{4}{3} - \frac{4 y}{3}$

Add $8$ and $0$ .

$8 = 8$

$x = \frac{4}{3} - \frac{4 y}{3}$

$8 = 8$

$x = \frac{4}{3} - \frac{4 y}{3}$

$8 = 8$

$x = \frac{4}{3} - \frac{4 y}{3}$

$8 = 8$

$x = \frac{4}{3} - \frac{4 y}{3}$

Remove any equations from the system that are always true.

$x = \frac{4}{3} - \frac{4 y}{3}$

Solve by Substitution 3x+4y=4 , 6x+8y=8

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