Solve by Substitution 3x+y=18 , y=3x

$3 x + y = 18$ , $y = 3 x$

Replace all occurrences of $y$ with $3 x$ in each equation.

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Replace all occurrences of $y$ in $3 x + y = 18$ with $3 x$ .

$3 x + 3 x = 18$

$y = 3 x$

Simplify $3 x + 3 x$ .

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Remove parentheses.

$3 x + 3 x = 18$

$y = 3 x$

Add $3 x$ and $3 x$ .

$6 x = 18$

$y = 3 x$

$6 x = 18$

$y = 3 x$

$6 x = 18$

$y = 3 x$

Divide each term by $6$ and simplify.

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Divide each term in $6 x = 18$ by $6$ .

$\frac{6 x}{6} = \frac{18}{6}$

$y = 3 x$

Cancel the common factor of $6$ .

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Cancel the common factor.

$\frac{6 x}{6} = \frac{18}{6}$

$y = 3 x$

Divide $x$ by $1$ .

$x = \frac{18}{6}$

$y = 3 x$

$x = \frac{18}{6}$

$y = 3 x$

Divide $18$ by $6$ .

$x = 3$

$y = 3 x$

$x = 3$

$y = 3 x$

Replace all occurrences of $x$ with $3$ in each equation.

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Replace all occurrences of $x$ in $y = 3 x$ with $3$ .

$y = 3 (3)$

$x = 3$

Multiply $3$ by $3$ .

$y = 9$

$x = 3$

$y = 9$

$x = 3$

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(3, 9)$

The result can be shown in multiple forms.

Point Form:

$(3, 9)$

Equation Form:

$x = 3, y = 9$

Solve by Substitution 3x+y=18 , y=3x

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