Solve by Substitution x+2y=13 , 4x+8y=-9

$x + 2 y = 13$ , $4 x + 8 y = - 9$

Subtract $2 y$ from both sides of the equation.

$x = 13 - 2 y$

$4 x + 8 y = - 9$

Replace all occurrences of $x$ with $13 - 2 y$ in each equation.

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Replace all occurrences of $x$ in $4 x + 8 y = - 9$ with $13 - 2 y$ .

$4 (13 - 2 y) + 8 y = - 9$

$x = 13 - 2 y$

Simplify $4 (13 - 2 y) + 8 y$ .

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Simplify each term.

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Apply the distributive property.

$4 \cdot 13 + 4 (- 2 y) + 8 y = - 9$

$x = 13 - 2 y$

Multiply $4$ by $13$ .

$52 + 4 (- 2 y) + 8 y = - 9$

$x = 13 - 2 y$

Multiply $- 2$ by $4$ .

$52 - 8 y + 8 y = - 9$

$x = 13 - 2 y$

$52 - 8 y + 8 y = - 9$

$x = 13 - 2 y$

Combine the opposite terms in $52 - 8 y + 8 y$ .

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Add $- 8 y$ and $8 y$ .

$52 + 0 = - 9$

$x = 13 - 2 y$

Add $52$ and $0$ .

$52 = - 9$

$x = 13 - 2 y$

$52 = - 9$

$x = 13 - 2 y$

$52 = - 9$

$x = 13 - 2 y$

$52 = - 9$

$x = 13 - 2 y$

Since $52 = - 9$ is not true, there is no solution.

No solution

Solve by Substitution x+2y=13 , 4x+8y=-9

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