Solve by Substitution y=5x-3 , y=x+1

$y = 5 x - 3$ , $y = x + 1$

Eliminate the equal sides of each equation and combine.

$5 x - 3 = x + 1$

Move all terms containing $x$ to the left side of the equation.

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Subtract $x$ from both sides of the equation.

$5 x - 3 - x = 1$

$y = x + 1$

Subtract $x$ from $5 x$ .

$4 x - 3 = 1$

$y = x + 1$

$4 x - 3 = 1$

$y = x + 1$

Move all terms not containing $x$ to the right side of the equation.

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Add $3$ to both sides of the equation.

$4 x = 1 + 3$

$y = x + 1$

Add $1$ and $3$ .

$4 x = 4$

$y = x + 1$

$4 x = 4$

$y = x + 1$

Divide each term by $4$ and simplify.

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Divide each term in $4 x = 4$ by $4$ .

$\frac{4 x}{4} = \frac{4}{4}$

$y = x + 1$

Cancel the common factor of $4$ .

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Cancel the common factor.

$\frac{4 x}{4} = \frac{4}{4}$

$y = x + 1$

Divide $x$ by $1$ .

$x = \frac{4}{4}$

$y = x + 1$

$x = \frac{4}{4}$

$y = x + 1$

Divide $4$ by $4$ .

$x = 1$

$y = x + 1$

$x = 1$

$y = x + 1$

Replace all occurrences of $x$ in $y = x + 1$ with $1$ .

$x = 1$

$y = (1) + 1$

Add $1$ and $1$ .

$x = 1$

$y = 2$

The solution to the system of equations can be represented as a point.

$(1, 2)$

The result can be shown in multiple forms.

Point Form:

$(1, 2)$

Equation Form:

$x = 1, y = 2$

Solve by Substitution y=5x-3 , y=x+1

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