Solve for a a(bc)=(ab)c

$a (b c) = (a b) c$

Remove parentheses.

$a b c = (a b) c$

Multiply $a b$ by $c$ .

$a b c = a b c$

Move all terms containing $a$ to the left side of the equation.

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Subtract $a b c$ from both sides of the equation.

$a b c - a b c = 0$

Subtract $a b c$ from $a b c$ .

$0 = 0$

Since $0 = 0$ , the equation will always be true.

Always true

The result can be shown in multiple forms.

Always true

Interval Notation:

$(- \infty, \infty)$

Solve for a a(bc)=(ab)c

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