2(3b-1)=40

Divide each term in 2(3b-1)=40 by 2.

2(3b-1)2=402

Cancel the common factor of 2.

Cancel the common factor.

2(3b-1)2=402

Divide 3b-1 by 1.

3b-1=402

3b-1=402

Divide 40 by 2.

3b-1=20

3b-1=20

Add 1 to both sides of the equation.

3b=20+1

Add 20 and 1.

3b=21

3b=21

Divide each term in 3b=21 by 3.

3b3=213

Cancel the common factor of 3.

Cancel the common factor.

3b3=213

Divide b by 1.

b=213

b=213

Divide 21 by 3.

b=7

b=7

Solve for b 2(3b-1)=40