Solve for b 2(3b-1)=40

Math
2(3b-1)=40
Divide each term by 2 and simplify.
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Divide each term in 2(3b-1)=40 by 2.
2(3b-1)2=402
Cancel the common factor of 2.
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Cancel the common factor.
2(3b-1)2=402
Divide 3b-1 by 1.
3b-1=402
3b-1=402
Divide 40 by 2.
3b-1=20
3b-1=20
Move all terms not containing b to the right side of the equation.
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Add 1 to both sides of the equation.
3b=20+1
Add 20 and 1.
3b=21
3b=21
Divide each term by 3 and simplify.
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Divide each term in 3b=21 by 3.
3b3=213
Cancel the common factor of 3.
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Cancel the common factor.
3b3=213
Divide b by 1.
b=213
b=213
Divide 21 by 3.
b=7
b=7
Solve for b 2(3b-1)=40

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