Solve for b 3^2+b^2=6^2

Math
32+b2=62
Raise 3 to the power of 2.
9+b2=62
Raise 6 to the power of 2.
9+b2=36
Move all terms not containing b to the right side of the equation.
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Subtract 9 from both sides of the equation.
b2=36-9
Subtract 9 from 36.
b2=27
b2=27
Take the square root of both sides of the equation to eliminate the exponent on the left side.
b=±27
The complete solution is the result of both the positive and negative portions of the solution.
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Simplify the right side of the equation.
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Rewrite 27 as 32⋅3.
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Factor 9 out of 27.
b=±9(3)
Rewrite 9 as 32.
b=±32⋅3
b=±32⋅3
Pull terms out from under the radical.
b=±33
b=±33
The complete solution is the result of both the positive and negative portions of the solution.
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First, use the positive value of the ± to find the first solution.
b=33
Next, use the negative value of the ± to find the second solution.
b=-33
The complete solution is the result of both the positive and negative portions of the solution.
b=33,-33
b=33,-33
b=33,-33
The result can be shown in multiple forms.
Exact Form:
b=33,-33
Decimal Form:
b=5.19615242…,-5.19615242…
Solve for b 3^2+b^2=6^2

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