Solve for b 4(b-2)=2(5-b)

$4 (b - 2) = 2 (5 - b)$

Simplify $4 (b - 2)$ .

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Apply the distributive property.

$4 b + 4 \cdot - 2 = 2 (5 - b)$

Multiply $4$ by $- 2$ .

$4 b - 8 = 2 (5 - b)$

Simplify $2 (5 - b)$ .

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Apply the distributive property.

$4 b - 8 = 2 \cdot 5 + 2 (- b)$

Multiply.

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Multiply $2$ by $5$ .

$4 b - 8 = 10 + 2 (- b)$

Multiply $- 1$ by $2$ .

$4 b - 8 = 10 - 2 b$

Move all terms containing $b$ to the left side of the equation.

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Add $2 b$ to both sides of the equation.

$4 b - 8 + 2 b = 10$

Add $4 b$ and $2 b$ .

$6 b - 8 = 10$

Move all terms not containing $b$ to the right side of the equation.

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Add $8$ to both sides of the equation.

$6 b = 10 + 8$

Add $10$ and $8$ .

$6 b = 18$

Divide each term by $6$ and simplify.

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Divide each term in $6 b = 18$ by $6$ .

$\frac{6 b}{6} = \frac{18}{6}$

Cancel the common factor of $6$ .

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Cancel the common factor.

$\frac{6 b}{6} = \frac{18}{6}$

Divide $b$ by $1$ .

$b = \frac{18}{6}$

Divide $18$ by $6$ .

$b = 3$

Solve for b 4(b-2)=2(5-b)

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