Solve for b A=(3C)/(a+b)

Math
A=3Ca+b
Rewrite the equation as 3Ca+b=A.
3Ca+b=A
Solve for b.
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Multiply each term by a+b and simplify.
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Multiply each term in 3Ca+b=A by a+b.
3Ca+b⋅(a+b)=A⋅(a+b)
Cancel the common factor of a+b.
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Cancel the common factor.
3Ca+b⋅(a+b)=A⋅(a+b)
Rewrite the expression.
3C=A⋅(a+b)
3C=A⋅(a+b)
Apply the distributive property.
3C=Aa+Ab
3C=Aa+Ab
Rewrite the equation as Aa+Ab=3C.
Aa+Ab=3C
Subtract Aa from both sides of the equation.
Ab=3C-Aa
Divide each term by A and simplify.
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Divide each term in Ab=3C-Aa by A.
AbA=3CA+-AaA
Cancel the common factor of A.
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Cancel the common factor.
AbA=3CA+-AaA
Divide b by 1.
b=3CA+-AaA
b=3CA+-AaA
Simplify each term.
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Cancel the common factor of A.
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Cancel the common factor.
b=3CA+-AaA
Divide -1a by 1.
b=3CA-1a
b=3CA-1a
Rewrite -1a as -a.
b=3CA-a
b=3CA-a
b=3CA-a
b=3CA-a
Solve for b A=(3C)/(a+b)

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