Solve for c 2=10c-4(2c-9)

$2 = 10 c - 4 (2 c - 9)$

Rewrite the equation as $10 c - 4 (2 c - 9) = 2$ .

$10 c - 4 (2 c - 9) = 2$

Simplify $10 c - 4 (2 c - 9)$ .

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Simplify each term.

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Apply the distributive property.

$10 c - 4 (2 c) - 4 \cdot - 9 = 2$

Multiply $2$ by $- 4$ .

$10 c - 8 c - 4 \cdot - 9 = 2$

Multiply $- 4$ by $- 9$ .

$10 c - 8 c + 36 = 2$

Subtract $8 c$ from $10 c$ .

$2 c + 36 = 2$

Move all terms not containing $c$ to the right side of the equation.

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Subtract $36$ from both sides of the equation.

$2 c = 2 - 36$

Subtract $36$ from $2$ .

$2 c = - 34$

Divide each term in $2 c = - 34$ by $2$ and simplify.

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Divide each term in $2 c = - 34$ by $2$ .

$\frac{2 c}{2} = \frac{- 34}{2}$

Simplify the left side.

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Cancel the common factor of $2$ .

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Cancel the common factor.

$\frac{2 c}{2} = \frac{- 34}{2}$

Divide $c$ by $1$ .

$c = \frac{- 34}{2}$

Simplify the right side.

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Divide $- 34$ by $2$ .

$c = - 17$

Solve for c 2=10c-4(2c-9)

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