Solve for d 0.5(7d+4)=7-1.5d

$0.5 (7 d + 4) = 7 - 1.5 d$

Simplify the left side.

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Apply the distributive property.

$0.5 (7 d) + 0.5 \cdot 4 = 7 - 1.5 d$

Multiply.

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Multiply $7$ by $0.5$ .

$3.5 d + 0.5 \cdot 4 = 7 - 1.5 d$

Multiply $0.5$ by $4$ .

$3.5 d + 2 = 7 - 1.5 d$

Move all terms containing $d$ to the left side of the equation.

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Add $- 1.5 d$ to both sides of the equation.

$3.5 d + 2 + 1.5 d = 7$

Add $3.5 d$ and $1.5 d$ .

$5 d + 2 = 7$

Move all terms not containing $d$ to the right side of the equation.

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Subtract $2$ from both sides of the equation.

$5 d = 7 - 2$

Subtract $2$ from $7$ .

$5 d = 5$

Divide each term by $5$ and simplify.

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Divide each term in $5 d = 5$ by $5$ .

$\frac{5 d}{5} = \frac{5}{5}$

Cancel the common factor of $5$ .

$d = \frac{5}{5}$

Divide $5$ by $5$ .

$d = 1$

Solve for d 0.5(7d+4)=7-1.5d

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