Solve for f 40=5/9(f-32)

$40 = \frac{5}{9} (f - 32)$

Rewrite the equation as $\frac{5}{9} \cdot (f - 32) = 40$ .

$\frac{5}{9} \cdot (f - 32) = 40$

Multiply both sides of the equation by $\frac{9}{5}$ .

$\frac{9}{5} \cdot \frac{5}{9} \cdot (f - 32) = \frac{9}{5} \cdot 40$

Simplify both sides of the equation.

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Simplify the left side.

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Cancel the common factor of $9$ .

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Cancel the common factor.

$\frac{9}{5} \cdot \frac{5}{9} \cdot (f - 32) = \frac{9}{5} \cdot 40$

Rewrite the expression.

$\frac{1}{5} \cdot 5 \cdot (f - 32) = \frac{9}{5} \cdot 40$

Cancel the common factor of $5$ .

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Cancel the common factor.

$\frac{1}{5} \cdot 5 \cdot (f - 32) = \frac{9}{5} \cdot 40$

Rewrite the expression.

$1 \cdot (f - 32) = \frac{9}{5} \cdot 40$

Multiply $f - 32$ by $1$ .

$f - 32 = \frac{9}{5} \cdot 40$

Simplify $\frac{9}{5} \cdot 40$ .

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Cancel the common factor of $5$ .

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Factor $5$ out of $40$ .

$f - 32 = \frac{9}{5} \cdot (5 (8))$

Cancel the common factor.

$f - 32 = \frac{9}{5} \cdot (5 \cdot 8)$

Rewrite the expression.

$f - 32 = 9 \cdot 8$

Multiply $9$ by $8$ .

$f - 32 = 72$

Move all terms not containing $f$ to the right side of the equation.

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Add $32$ to both sides of the equation.

$f = 72 + 32$

Add $72$ and $32$ .

$f = 104$

Solve for f 40=5/9(f-32)

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