Solve for g 6(-2g-1)=-(13g+2)

$6 (- 2 g - 1) = - (13 g + 2)$

Simplify the left side.

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Apply the distributive property.

$6 (- 2 g) + 6 \cdot - 1 = - (13 g + 2)$

Multiply.

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Multiply $- 2$ by $6$ .

$- 12 g + 6 \cdot - 1 = - (13 g + 2)$

Multiply $6$ by $- 1$ .

$- 12 g - 6 = - (13 g + 2)$

Simplify $- (13 g + 2)$ .

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Apply the distributive property.

$- 12 g - 6 = - (13 g) - 1 \cdot 2$

Multiply.

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Multiply $13$ by $- 1$ .

$- 12 g - 6 = - 13 g - 1 \cdot 2$

Multiply $- 1$ by $2$ .

$- 12 g - 6 = - 13 g - 2$

Move all terms containing $g$ to the left side of the equation.

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Add $- 13 g$ to both sides of the equation.

$- 12 g - 6 + 13 g = - 2$

Add $- 12 g$ and $13 g$ .

$g - 6 = - 2$

Move all terms not containing $g$ to the right side of the equation.

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Add $6$ to both sides of the equation.

$g = - 2 + 6$

Add $- 2$ and $6$ .

$g = 4$

Solve for g 6(-2g-1)=-(13g+2)

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