Solve for x 10^(x+1)=1/1000

$10^{x + 1} = \frac{1}{1000}$

Raise $1000$ to the power of $1$ .

$10^{x + 1} = \frac{1}{1000^{1}}$

Move $1000^{1}$ to the numerator using the negative exponent rule $\frac{1}{b^{n}} = b^{- n}$ .

$10^{x + 1} = 1000^{- 1}$

Create equivalent expressions in the equation that all have equal bases.

$10^{x + 1} = 10^{- 3}$

Since the bases are the same, then two expressions are only equal if the exponents are also equal.

$x + 1 = - 3$

Move all terms not containing $x$ to the right side of the equation.

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Subtract $1$ from both sides of the equation.

$x = - 3 - 1$

Subtract $1$ from $- 3$ .

$x = - 4$

Solve for x 10^(x+1)=1/1000

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