Solve for x -2/3x=10

$- \frac{2}{3} x = 10$

Multiply both sides of the equation by $- \frac{3}{2}$ .

$- \frac{3}{2} \cdot (- \frac{2}{3}) \cdot x = - \frac{3}{2} \cdot 10$

Simplify both sides of the equation.

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Simplify $- \frac{3}{2} \cdot (- \frac{2}{3}) \cdot x$ .

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Cancel the common factor of $3$ .

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Move the leading negative in $- \frac{3}{2}$ into the numerator.

$\frac{- 3}{2} \cdot (- \frac{2}{3}) \cdot x = - \frac{3}{2} \cdot 10$

Move the leading negative in $- \frac{2}{3}$ into the numerator.

$\frac{- 3}{2} \cdot \frac{- 2}{3} \cdot x = - \frac{3}{2} \cdot 10$

Factor $3$ out of $- 3$ .

$\frac{3 (- 1)}{2} \cdot \frac{- 2}{3} \cdot x = - \frac{3}{2} \cdot 10$

Cancel the common factor.

$\frac{3 \cdot - 1}{2} \cdot \frac{- 2}{3} \cdot x = - \frac{3}{2} \cdot 10$

Rewrite the expression.

$\frac{- 1}{2} \cdot - 2 \cdot x = - \frac{3}{2} \cdot 10$

Cancel the common factor of $2$ .

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Factor $2$ out of $- 2$ .

$\frac{- 1}{2} \cdot (2 (- 1)) \cdot x = - \frac{3}{2} \cdot 10$

Cancel the common factor.

$\frac{- 1}{2} \cdot (2 \cdot - 1) \cdot x = - \frac{3}{2} \cdot 10$

Rewrite the expression.

$- 1 \cdot - 1 \cdot x = - \frac{3}{2} \cdot 10$

Multiply.

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Multiply $- 1$ by $- 1$ .

$1 \cdot x = - \frac{3}{2} \cdot 10$

Multiply $x$ by $1$ .

$x = - \frac{3}{2} \cdot 10$

Simplify $- \frac{3}{2} \cdot 10$ .

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Cancel the common factor of $2$ .

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Move the leading negative in $- \frac{3}{2}$ into the numerator.

$x = \frac{- 3}{2} \cdot 10$

Factor $2$ out of $10$ .

$x = \frac{- 3}{2} \cdot (2 (5))$

Cancel the common factor.

$x = \frac{- 3}{2} \cdot (2 \cdot 5)$

Rewrite the expression.

$x = - 3 \cdot 5$

Multiply $- 3$ by $5$ .

$x = - 15$

Solve for x -2/3x=10

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