Solve for x 2(x-4)=3(1+x)

$2 (x - 4) = 3 (1 + x)$

Simplify $2 (x - 4)$ .

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Apply the distributive property.

$2 x + 2 \cdot - 4 = 3 (1 + x)$

Multiply $2$ by $- 4$ .

$2 x - 8 = 3 (1 + x)$

Simplify $3 (1 + x)$ .

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Apply the distributive property.

$2 x - 8 = 3 \cdot 1 + 3 x$

Multiply $3$ by $1$ .

$2 x - 8 = 3 + 3 x$

Move all terms containing $x$ to the left side of the equation.

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Subtract $3 x$ from both sides of the equation.

$2 x - 8 - 3 x = 3$

Subtract $3 x$ from $2 x$ .

$- x - 8 = 3$

Move all terms not containing $x$ to the right side of the equation.

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Add $8$ to both sides of the equation.

$- x = 3 + 8$

Add $3$ and $8$ .

$- x = 11$

Multiply each term in $- x = 11$ by $- 1$

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Multiply each term in $- x = 11$ by $- 1$ .

$(- x) \cdot - 1 = 11 \cdot - 1$

Multiply $(- x) \cdot - 1$ .

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Multiply $- 1$ by $- 1$ .

$1 x = 11 \cdot - 1$

Multiply $x$ by $1$ .

$x = 11 \cdot - 1$

Multiply $11$ by $- 1$ .

$x = - 11$

Solve for x 2(x-4)=3(1+x)

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