Solve for x 3(1-3x)=2(-4x+7)

$3 (1 - 3 x) = 2 (- 4 x + 7)$

Simplify $3 (1 - 3 x)$ .

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Apply the distributive property.

$3 \cdot 1 + 3 (- 3 x) = 2 (- 4 x + 7)$

Multiply.

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Multiply $3$ by $1$ .

$3 + 3 (- 3 x) = 2 (- 4 x + 7)$

Multiply $- 3$ by $3$ .

$3 - 9 x = 2 (- 4 x + 7)$

Simplify $2 (- 4 x + 7)$ .

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Apply the distributive property.

$3 - 9 x = 2 (- 4 x) + 2 \cdot 7$

Multiply.

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Multiply $- 4$ by $2$ .

$3 - 9 x = - 8 x + 2 \cdot 7$

Multiply $2$ by $7$ .

$3 - 9 x = - 8 x + 14$

Move all terms containing $x$ to the left side of the equation.

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Add $8 x$ to both sides of the equation.

$3 - 9 x + 8 x = 14$

Add $- 9 x$ and $8 x$ .

$3 - x = 14$

Move all terms not containing $x$ to the right side of the equation.

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Subtract $3$ from both sides of the equation.

$- x = 14 - 3$

Subtract $3$ from $14$ .

$- x = 11$

Multiply each term in $- x = 11$ by $- 1$

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Multiply each term in $- x = 11$ by $- 1$ .

$(- x) \cdot - 1 = 11 \cdot - 1$

Multiply $(- x) \cdot - 1$ .

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Multiply $- 1$ by $- 1$ .

$1 x = 11 \cdot - 1$

Multiply $x$ by $1$ .

$x = 11 \cdot - 1$

Multiply $11$ by $- 1$ .

$x = - 11$

Solve for x 3(1-3x)=2(-4x+7)

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