Solve for x 3x+c=cx-2

Math
3x+c=cx-2
Subtract cx from both sides of the equation.
3x+c-cx=-2
Subtract c from both sides of the equation.
3x-cx=-2-c
Factor x out of 3x-cx.
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Factor x out of 3x.
x⋅3-cx=-2-c
Factor x out of -cx.
x⋅3+x(-c)=-2-c
Factor x out of x⋅3+x(-c).
x(3-c)=-2-c
x(3-c)=-2-c
Divide each term by 3-c and simplify.
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Divide each term in x(3-c)=-2-c by 3-c.
x(3-c)3-c=-23-c+-c3-c
Cancel the common factor of 3-c.
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Cancel the common factor.
x(3-c)3-c=-23-c+-c3-c
Divide x by 1.
x=-23-c+-c3-c
x=-23-c+-c3-c
Simplify -23-c+-c3-c.
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Simplify each term.
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Move the negative in front of the fraction.
x=-23-c+-c3-c
Move the negative in front of the fraction.
x=-23-c-c3-c
x=-23-c-c3-c
Simplify terms.
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Combine the numerators over the common denominator.
x=-2-c3-c
Rewrite -2 as -1(2).
x=-1(2)-c3-c
Factor -1 out of -c.
x=-1(2)-(c)3-c
Factor -1 out of -1(2)-(c).
x=-1(2+c)3-c
Move the negative in front of the fraction.
x=-2+c3-c
x=-2+c3-c
x=-2+c3-c
x=-2+c3-c
Solve for x 3x+c=cx-2

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