Solve for x -(4-x)=3/4*(x-6)

$- (4 - x) = \frac{3}{4} \cdot (x - 6)$

Simplify $- (4 - x)$ .

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Apply the distributive property.

$- 1 \cdot 4 - - x = \frac{3}{4} \cdot (x - 6)$

Multiply $- 1$ by $4$ .

$- 4 - - x = \frac{3}{4} \cdot (x - 6)$

Multiply $- - x$ .

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Multiply $- 1$ by $- 1$ .

$- 4 + 1 x = \frac{3}{4} \cdot (x - 6)$

Multiply $x$ by $1$ .

$- 4 + x = \frac{3}{4} \cdot (x - 6)$

Simplify $\frac{3}{4} \cdot (x - 6)$ .

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Apply the distributive property.

$- 4 + x = \frac{3}{4} x + \frac{3}{4} \cdot - 6$

Combine $\frac{3}{4}$ and $x$ .

$- 4 + x = \frac{3 x}{4} + \frac{3}{4} \cdot - 6$

Cancel the common factor of $2$ .

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Factor $2$ out of $4$ .

$- 4 + x = \frac{3 x}{4} + \frac{3}{2 (2)} \cdot - 6$

Factor $2$ out of $- 6$ .

$- 4 + x = \frac{3 x}{4} + \frac{3}{2 \cdot 2} \cdot (2 \cdot - 3)$

Cancel the common factor.

$- 4 + x = \frac{3 x}{4} + \frac{3}{2 \cdot 2} \cdot (2 \cdot - 3)$

Rewrite the expression.

$- 4 + x = \frac{3 x}{4} + \frac{3}{2} \cdot - 3$

Combine $\frac{3}{2}$ and $- 3$ .

$- 4 + x = \frac{3 x}{4} + \frac{3 \cdot - 3}{2}$

Simplify the expression.

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Multiply $3$ by $- 3$ .

$- 4 + x = \frac{3 x}{4} + \frac{- 9}{2}$

Move the negative in front of the fraction.

$- 4 + x = \frac{3 x}{4} - \frac{9}{2}$

Move all terms containing $x$ to the left side of the equation.

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Subtract $\frac{3 x}{4}$ from both sides of the equation.

$- 4 + x - \frac{3 x}{4} = - \frac{9}{2}$

To write $x$ as a fraction with a common denominator, multiply by $\frac{4}{4}$ .

$- 4 + x \cdot \frac{4}{4} - \frac{3 x}{4} = - \frac{9}{2}$

Combine $x$ and $\frac{4}{4}$ .

$- 4 + \frac{x \cdot 4}{4} - \frac{3 x}{4} = - \frac{9}{2}$

Combine the numerators over the common denominator.

$- 4 + \frac{x \cdot 4 - 3 x}{4} = - \frac{9}{2}$

Subtract $3 x$ from $x \cdot 4$ .

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Reorder $x$ and $4$ .

$- 4 + \frac{4 \cdot x - 3 x}{4} = - \frac{9}{2}$

Subtract $3 x$ from $4 \cdot x$ .

$- 4 + \frac{x}{4} = - \frac{9}{2}$

Move all terms not containing $x$ to the right side of the equation.

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Add $4$ to both sides of the equation.

$\frac{x}{4} = - \frac{9}{2} + 4$

To write $4$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$\frac{x}{4} = - \frac{9}{2} + 4 \cdot \frac{2}{2}$

Combine $4$ and $\frac{2}{2}$ .

$\frac{x}{4} = - \frac{9}{2} + \frac{4 \cdot 2}{2}$

Combine the numerators over the common denominator.

$\frac{x}{4} = \frac{- 9 + 4 \cdot 2}{2}$

Simplify the numerator.

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Multiply $4$ by $2$ .

$\frac{x}{4} = \frac{- 9 + 8}{2}$

Add $- 9$ and $8$ .

$\frac{x}{4} = \frac{- 1}{2}$

Move the negative in front of the fraction.

$\frac{x}{4} = - \frac{1}{2}$

Multiply both sides of the equation by $4$ .

$4 \cdot \frac{x}{4} = 4 \cdot (- \frac{1}{2})$

Simplify both sides of the equation.

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Cancel the common factor of $4$ .

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Cancel the common factor.

$4 \cdot \frac{x}{4} = 4 \cdot (- \frac{1}{2})$

Rewrite the expression.

$x = 4 \cdot (- \frac{1}{2})$

Simplify $4 \cdot (- \frac{1}{2})$ .

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Cancel the common factor of $2$ .

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Move the leading negative in $- \frac{1}{2}$ into the numerator.

$x = 4 \cdot \frac{- 1}{2}$

Factor $2$ out of $4$ .

$x = 2 (2) \cdot \frac{- 1}{2}$

Cancel the common factor.

$x = 2 \cdot 2 \cdot \frac{- 1}{2}$

Rewrite the expression.

$x = 2 \cdot - 1$

Multiply $2$ by $- 1$ .

$x = - 2$

Solve for x -(4-x)=3/4*(x-6)

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