Solve for x 7x+3(2x+5)=10x+17

Math
7x+3(2x+5)=10x+17
Simplify 7x+3(2x+5).
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Simplify each term.
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Apply the distributive property.
7x+3(2x)+3⋅5=10x+17
Multiply 2 by 3.
7x+6x+3⋅5=10x+17
Multiply 3 by 5.
7x+6x+15=10x+17
7x+6x+15=10x+17
Add 7x and 6x.
13x+15=10x+17
13x+15=10x+17
Move all terms containing x to the left side of the equation.
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Subtract 10x from both sides of the equation.
13x+15-10x=17
Subtract 10x from 13x.
3x+15=17
3x+15=17
Move all terms not containing x to the right side of the equation.
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Subtract 15 from both sides of the equation.
3x=17-15
Subtract 15 from 17.
3x=2
3x=2
Divide each term by 3 and simplify.
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Divide each term in 3x=2 by 3.
3×3=23
Cancel the common factor of 3.
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Cancel the common factor.
3×3=23
Divide x by 1.
x=23
x=23
x=23
The result can be shown in multiple forms.
Exact Form:
x=23
Decimal Form:
x=0.6‾
Solve for x 7x+3(2x+5)=10x+17

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