Solve for x A=Bxt+C - MathMaster

$A = B x t + C$

Rewrite the equation as $B x t + C = A$ .

$B x t + C = A$

Subtract $C$ from both sides of the equation.

$B x t = A - C$

Divide each term by $B t$ and simplify.

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Divide each term in $B x t = A - C$ by $B t$ .

$\frac{B x t}{B t} = \frac{A}{B t} + \frac{- C}{B t}$

Simplify $\frac{B x t}{B t}$ .

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Cancel the common factor of $B$ .

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Cancel the common factor.

$\frac{B x t}{B t} = \frac{A}{B t} + \frac{- C}{B t}$

Rewrite the expression.

$\frac{x t}{t} = \frac{A}{B t} + \frac{- C}{B t}$

Cancel the common factor of $t$ .

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Cancel the common factor.

$\frac{x t}{t} = \frac{A}{B t} + \frac{- C}{B t}$

Divide $x$ by $1$ .

$x = \frac{A}{B t} + \frac{- C}{B t}$

Move the negative in front of the fraction.

$x = \frac{A}{B t} - \frac{C}{B t}$

Solve for x A=Bxt+C

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