Solve for x log base x of 25=-2

$\log_{x} (25) = - 2$

Rewrite $\log_{x} (25) = - 2$ in exponential form using the definition of a logarithm. If $x$ and $b$ are positive real numbers and $b$ $\neq$ $1$ , then $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ .

$x^{- 2} = 25$

Solve for $x$

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Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{1}{x^{2}} = 25$

Solve for $x$ .

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Multiply each term by $x^{2}$ and simplify.

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Multiply each term in $\frac{1}{x^{2}} = 25$ by $x^{2}$ .

$\frac{1}{x^{2}} \cdot x^{2} = 25 \cdot x^{2}$

Cancel the common factor of $x^{2}$ .

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Cancel the common factor.

$\frac{1}{x^{2}} \cdot x^{2} = 25 \cdot x^{2}$

Rewrite the expression.

$1 = 25 \cdot x^{2}$

$1 = 25 x^{2}$

Rewrite the equation as $25 x^{2} = 1$ .

$25 x^{2} = 1$

Divide each term by $25$ and simplify.

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Divide each term in $25 x^{2} = 1$ by $25$ .

$\frac{25 x^{2}}{25} = \frac{1}{25}$

Cancel the common factor of $25$ .

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Cancel the common factor.

$\frac{25 x^{2}}{25} = \frac{1}{25}$

Divide $x^{2}$ by $1$ .

$x^{2} = \frac{1}{25}$

Take the $square$ root of both sides of the $equation$ to eliminate the exponent on the left side.

$x = \pm \sqrt{\frac{1}{25}}$

The complete solution is the result of both the positive and negative portions of the solution.

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Simplify the right side of the equation.

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Rewrite $\sqrt{\frac{1}{25}}$ as $\frac{\sqrt{1}}{\sqrt{25}}$ .

$x = \pm \frac{\sqrt{1}}{\sqrt{25}}$

Any root of $1$ is $1$ .

$x = \pm \frac{1}{\sqrt{25}}$

Simplify the denominator.

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Rewrite $25$ as $5^{2}$ .

$x = \pm \frac{1}{\sqrt{5^{2}}}$

Pull terms out from under the radical, assuming positive real numbers.

$x = \pm \frac{1}{5}$

The complete solution is the result of both the positive and negative portions of the solution.

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First, use the positive value of the $\pm$ to find the first solution.

$x = \frac{1}{5}$

Next, use the negative value of the $\pm$ to find the second solution.

$x = - \frac{1}{5}$

The complete solution is the result of both the positive and negative portions of the solution.

$x = \frac{1}{5}, - \frac{1}{5}$

Exclude the solutions that do not make $\log_{x} (25) = - 2$ true.

$x = \frac{1}{5}$

The result can be shown in multiple forms.

Exact Form:

$x = \frac{1}{5}$

Decimal Form:

$x = 0.2$

Solve for x log base x of 25=-2

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