Solve for x x/4-2/3=7/12

$\frac{x}{4} - \frac{2}{3} = \frac{7}{12}$

Move all terms not containing $x$ to the right side of the equation.

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Add $\frac{2}{3}$ to both sides of the equation.

$\frac{x}{4} = \frac{7}{12} + \frac{2}{3}$

To write $\frac{2}{3}$ as a fraction with a common denominator, multiply by $\frac{4}{4}$ .

$\frac{x}{4} = \frac{7}{12} + \frac{2}{3} \cdot \frac{4}{4}$

Write each expression with a common denominator of $12$ , by multiplying each by an appropriate factor of $1$ .

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Multiply $\frac{2}{3}$ and $\frac{4}{4}$ .

$\frac{x}{4} = \frac{7}{12} + \frac{2 \cdot 4}{3 \cdot 4}$

Multiply $3$ by $4$ .

$\frac{x}{4} = \frac{7}{12} + \frac{2 \cdot 4}{12}$

Combine the numerators over the common denominator.

$\frac{x}{4} = \frac{7 + 2 \cdot 4}{12}$

Simplify the numerator.

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Multiply $2$ by $4$ .

$\frac{x}{4} = \frac{7 + 8}{12}$

Add $7$ and $8$ .

$\frac{x}{4} = \frac{15}{12}$

Cancel the common factor of $15$ and $12$ .

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Factor $3$ out of $15$ .

$\frac{x}{4} = \frac{3 (5)}{12}$

Cancel the common factors.

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Factor $3$ out of $12$ .

$\frac{x}{4} = \frac{3 \cdot 5}{3 \cdot 4}$

Cancel the common factor.

$\frac{x}{4} = \frac{3 \cdot 5}{3 \cdot 4}$

Rewrite the expression.

$\frac{x}{4} = \frac{5}{4}$

Since the expression on each side of the equation has the same denominator, the numerators must be equal.

$x = 5$

Solve for x x/4-2/3=7/12

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