Solve for x x^2-8x=48

Math
x2-8x=48
Move 48 to the left side of the equation by subtracting it from both sides.
x2-8x-48=0
Factor x2-8x-48 using the AC method.
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Consider the form x2+bx+c. Find a pair of integers whose product is c and whose sum is b. In this case, whose product is -48 and whose sum is -8.
-12,4
Write the factored form using these integers.
(x-12)(x+4)=0
(x-12)(x+4)=0
If any individual factor on the left side of the equation is equal to 0, the entire expression will be equal to 0.
x-12=0
x+4=0
Set the first factor equal to 0 and solve.
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Set the first factor equal to 0.
x-12=0
Add 12 to both sides of the equation.
x=12
x=12
Set the next factor equal to 0 and solve.
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Set the next factor equal to 0.
x+4=0
Subtract 4 from both sides of the equation.
x=-4
x=-4
The final solution is all the values that make (x-12)(x+4)=0 true.
x=12,-4
Solve for x x^2-8x=48

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