Solve for z 4z-3(z+2)=2(1-3z)

$4 z - 3 (z + 2) = 2 (1 - 3 z)$

Simplify $4 z - 3 (z + 2)$ .

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Simplify each term.

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Apply the distributive property.

$4 z - 3 z - 3 \cdot 2 = 2 (1 - 3 z)$

Multiply $- 3$ by $2$ .

$4 z - 3 z - 6 = 2 (1 - 3 z)$

Subtract $3 z$ from $4 z$ .

$z - 6 = 2 (1 - 3 z)$

Simplify $2 (1 - 3 z)$ .

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Apply the distributive property.

$z - 6 = 2 \cdot 1 + 2 (- 3 z)$

Multiply.

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Multiply $2$ by $1$ .

$z - 6 = 2 + 2 (- 3 z)$

Multiply $- 3$ by $2$ .

$z - 6 = 2 - 6 z$

Move all terms containing $z$ to the left side of the equation.

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Add $6 z$ to both sides of the equation.

$z - 6 + 6 z = 2$

Add $z$ and $6 z$ .

$7 z - 6 = 2$

Move all terms not containing $z$ to the right side of the equation.

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Add $6$ to both sides of the equation.

$7 z = 2 + 6$

Add $2$ and $6$ .

$7 z = 8$

Divide each term by $7$ and simplify.

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Divide each term in $7 z = 8$ by $7$ .

$\frac{7 z}{7} = \frac{8}{7}$

Cancel the common factor of $7$ .

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Cancel the common factor.

$\frac{7 z}{7} = \frac{8}{7}$

Divide $z$ by $1$ .

$z = \frac{8}{7}$

The result can be shown in multiple forms.

Exact Form:

$z = \frac{8}{7}$

Decimal Form:

$z = 1.\overline{142857}$

Mixed Number Form:

$z = 1 \frac{1}{7}$

Solve for z 4z-3(z+2)=2(1-3z)

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