Solve using the Square Root Property 2x^2+4=9x

Math
2×2+4=9x
Subtract 9x from both sides of the equation.
2×2+4-9x=0
Factor by grouping.
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Reorder terms.
2×2-9x+4=0
For a polynomial of the form ax2+bx+c, rewrite the middle term as a sum of two terms whose product is a⋅c=2⋅4=8 and whose sum is b=-9.
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Factor -9 out of -9x.
2×2-9x+4=0
Rewrite -9 as -1 plus -8
2×2+(-1-8)x+4=0
Apply the distributive property.
2×2-1x-8x+4=0
2×2-1x-8x+4=0
Factor out the greatest common factor from each group.
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Group the first two terms and the last two terms.
(2×2-1x)-8x+4=0
Factor out the greatest common factor (GCF) from each group.
x(2x-1)-4(2x-1)=0
x(2x-1)-4(2x-1)=0
Factor the polynomial by factoring out the greatest common factor, 2x-1.
(2x-1)(x-4)=0
(2x-1)(x-4)=0
If any individual factor on the left side of the equation is equal to 0, the entire expression will be equal to 0.
2x-1=0
x-4=0
Set the first factor equal to 0 and solve.
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Set the first factor equal to 0.
2x-1=0
Add 1 to both sides of the equation.
2x=1
Divide each term by 2 and simplify.
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Divide each term in 2x=1 by 2.
2×2=12
Cancel the common factor of 2.
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Cancel the common factor.
2×2=12
Divide x by 1.
x=12
x=12
x=12
x=12
Set the next factor equal to 0 and solve.
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Set the next factor equal to 0.
x-4=0
Add 4 to both sides of the equation.
x=4
x=4
The final solution is all the values that make (2x-1)(x-4)=0 true.
x=12,4
Solve using the Square Root Property 2x^2+4=9x

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