Solve using the Square Root Property 3=3x^2-5x+5

Math
3=3×2-5x+5
Rewrite the equation as 3×2-5x+5=3.
3×2-5x+5=3
Move 3 to the left side of the equation by subtracting it from both sides.
3×2-5x+5-3=0
Subtract 3 from 5.
3×2-5x+2=0
Factor by grouping.
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For a polynomial of the form ax2+bx+c, rewrite the middle term as a sum of two terms whose product is a⋅c=3⋅2=6 and whose sum is b=-5.
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Factor -5 out of -5x.
3×2-5x+2=0
Rewrite -5 as -2 plus -3
3×2+(-2-3)x+2=0
Apply the distributive property.
3×2-2x-3x+2=0
3×2-2x-3x+2=0
Factor out the greatest common factor from each group.
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Group the first two terms and the last two terms.
(3×2-2x)-3x+2=0
Factor out the greatest common factor (GCF) from each group.
x(3x-2)-(3x-2)=0
x(3x-2)-(3x-2)=0
Factor the polynomial by factoring out the greatest common factor, 3x-2.
(3x-2)(x-1)=0
(3x-2)(x-1)=0
If any individual factor on the left side of the equation is equal to 0, the entire expression will be equal to 0.
3x-2=0
x-1=0
Set the first factor equal to 0 and solve.
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Set the first factor equal to 0.
3x-2=0
Add 2 to both sides of the equation.
3x=2
Divide each term by 3 and simplify.
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Divide each term in 3x=2 by 3.
3×3=23
Cancel the common factor of 3.
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Cancel the common factor.
3×3=23
Divide x by 1.
x=23
x=23
x=23
x=23
Set the next factor equal to 0 and solve.
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Set the next factor equal to 0.
x-1=0
Add 1 to both sides of the equation.
x=1
x=1
The final solution is all the values that make (3x-2)(x-1)=0 true.
x=23,1
Solve using the Square Root Property 3=3x^2-5x+5

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