Solve Using the Square Root Property 36=x^2-5x

Math
36=x2-5x
Rewrite the equation as x2-5x=36.
x2-5x=36
Move 36 to the left side of the equation by subtracting it from both sides.
x2-5x-36=0
Factor x2-5x-36 using the AC method.
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Consider the form x2+bx+c. Find a pair of integers whose product is c and whose sum is b. In this case, whose product is -36 and whose sum is -5.
-9,4
Write the factored form using these integers.
(x-9)(x+4)=0
(x-9)(x+4)=0
If any individual factor on the left side of the equation is equal to 0, the entire expression will be equal to 0.
x-9=0
x+4=0
Set the first factor equal to 0 and solve.
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Set the first factor equal to 0.
x-9=0
Add 9 to both sides of the equation.
x=9
x=9
Set the next factor equal to 0 and solve.
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Set the next factor equal to 0.
x+4=0
Subtract 4 from both sides of the equation.
x=-4
x=-4
The final solution is all the values that make (x-9)(x+4)=0 true.
x=9,-4
Solve Using the Square Root Property 36=x^2-5x

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