Solve using the Square Root Property 3x^2-16x-7=5

Math
3×2-16x-7=5
Move 5 to the left side of the equation by subtracting it from both sides.
3×2-16x-7-5=0
Subtract 5 from -7.
3×2-16x-12=0
Factor by grouping.
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For a polynomial of the form ax2+bx+c, rewrite the middle term as a sum of two terms whose product is a⋅c=3⋅-12=-36 and whose sum is b=-16.
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Factor -16 out of -16x.
3×2-16x-12=0
Rewrite -16 as 2 plus -18
3×2+(2-18)x-12=0
Apply the distributive property.
3×2+2x-18x-12=0
3×2+2x-18x-12=0
Factor out the greatest common factor from each group.
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Group the first two terms and the last two terms.
(3×2+2x)-18x-12=0
Factor out the greatest common factor (GCF) from each group.
x(3x+2)-6(3x+2)=0
x(3x+2)-6(3x+2)=0
Factor the polynomial by factoring out the greatest common factor, 3x+2.
(3x+2)(x-6)=0
(3x+2)(x-6)=0
If any individual factor on the left side of the equation is equal to 0, the entire expression will be equal to 0.
3x+2=0
x-6=0
Set the first factor equal to 0 and solve.
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Set the first factor equal to 0.
3x+2=0
Subtract 2 from both sides of the equation.
3x=-2
Divide each term by 3 and simplify.
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Divide each term in 3x=-2 by 3.
3×3=-23
Cancel the common factor of 3.
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Cancel the common factor.
3×3=-23
Divide x by 1.
x=-23
x=-23
Move the negative in front of the fraction.
x=-23
x=-23
x=-23
Set the next factor equal to 0 and solve.
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Set the next factor equal to 0.
x-6=0
Add 6 to both sides of the equation.
x=6
x=6
The final solution is all the values that make (3x+2)(x-6)=0 true.
x=-23,6
Solve using the Square Root Property 3x^2-16x-7=5

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