Solve using the Square Root Property 7x^2+2x-5=0

Math
7×2+2x-5=0
Factor by grouping.
Tap for more steps…
For a polynomial of the form ax2+bx+c, rewrite the middle term as a sum of two terms whose product is a⋅c=7⋅-5=-35 and whose sum is b=2.
Tap for more steps…
Factor 2 out of 2x.
7×2+2(x)-5=0
Rewrite 2 as -5 plus 7
7×2+(-5+7)x-5=0
Apply the distributive property.
7×2-5x+7x-5=0
7×2-5x+7x-5=0
Factor out the greatest common factor from each group.
Tap for more steps…
Group the first two terms and the last two terms.
(7×2-5x)+7x-5=0
Factor out the greatest common factor (GCF) from each group.
x(7x-5)+1(7x-5)=0
x(7x-5)+1(7x-5)=0
Factor the polynomial by factoring out the greatest common factor, 7x-5.
(7x-5)(x+1)=0
(7x-5)(x+1)=0
If any individual factor on the left side of the equation is equal to 0, the entire expression will be equal to 0.
7x-5=0
x+1=0
Set the first factor equal to 0 and solve.
Tap for more steps…
Set the first factor equal to 0.
7x-5=0
Add 5 to both sides of the equation.
7x=5
Divide each term by 7 and simplify.
Tap for more steps…
Divide each term in 7x=5 by 7.
7×7=57
Cancel the common factor of 7.
Tap for more steps…
Cancel the common factor.
7×7=57
Divide x by 1.
x=57
x=57
x=57
x=57
Set the next factor equal to 0 and solve.
Tap for more steps…
Set the next factor equal to 0.
x+1=0
Subtract 1 from both sides of the equation.
x=-1
x=-1
The final solution is all the values that make (7x-5)(x+1)=0 true.
x=57,-1
Solve using the Square Root Property 7x^2+2x-5=0

Download our
App from the store

Create a High Performed UI/UX Design from a Silicon Valley.

Scroll to top