Solve Using the Square Root Property 8x+12=3x^2+6x

$8 x + 12 = 3 x^{2} + 6 x$

Since $x$ is on the right side of the equation, switch the sides so it is on the left side of the equation.

$3 x^{2} + 6 x = 8 x + 12$

Move all terms containing $x$ to the left side of the equation.

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Subtract $8 x$ from both sides of the equation.

$3 x^{2} + 6 x - 8 x = 12$

Subtract $8 x$ from $6 x$ .

$3 x^{2} - 2 x = 12$

Move $12$ to the left side of the equation by subtracting it from both sides.

$3 x^{2} - 2 x - 12 = 0$

Use the quadratic formula to find the solutions.

$\frac{- b \pm \sqrt{b^{2} - 4 (a c)}}{2 a}$

Substitute the values $a = 3$ , $b = - 2$ , and $c = - 12$ into the quadratic formula and solve for $x$ .

$\frac{2 \pm \sqrt{{(- 2)}^{2} - 4 \cdot (3 \cdot - 12)}}{2 \cdot 3}$

Simplify.

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Simplify the numerator.

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Raise $- 2$ to the power of $2$ .

$x = \frac{2 \pm \sqrt{4 - 4 \cdot (3 \cdot - 12)}}{2 \cdot 3}$

Multiply $3$ by $- 12$ .

$x = \frac{2 \pm \sqrt{4 - 4 \cdot - 36}}{2 \cdot 3}$

Multiply $- 4$ by $- 36$ .

$x = \frac{2 \pm \sqrt{4 + 144}}{2 \cdot 3}$

Add $4$ and $144$ .

$x = \frac{2 \pm \sqrt{148}}{2 \cdot 3}$

Rewrite $148$ as $2^{2} \cdot 37$ .

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Factor $4$ out of $148$ .

$x = \frac{2 \pm \sqrt{4 (37)}}{2 \cdot 3}$

Rewrite $4$ as $2^{2}$ .

$x = \frac{2 \pm \sqrt{2^{2} \cdot 37}}{2 \cdot 3}$

Pull terms out from under the radical.

$x = \frac{2 \pm 2 \sqrt{37}}{2 \cdot 3}$

Multiply $2$ by $3$ .

$x = \frac{2 \pm 2 \sqrt{37}}{6}$

Simplify $\frac{2 \pm 2 \sqrt{37}}{6}$ .

$x = \frac{1 \pm \sqrt{37}}{3}$

Simplify the expression to solve for the $+$ portion of the $\pm$ .

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Simplify the numerator.

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Raise $- 2$ to the power of $2$ .

$x = \frac{2 \pm \sqrt{4 - 4 \cdot (3 \cdot - 12)}}{2 \cdot 3}$

Multiply $3$ by $- 12$ .

$x = \frac{2 \pm \sqrt{4 - 4 \cdot - 36}}{2 \cdot 3}$

Multiply $- 4$ by $- 36$ .

$x = \frac{2 \pm \sqrt{4 + 144}}{2 \cdot 3}$

Add $4$ and $144$ .

$x = \frac{2 \pm \sqrt{148}}{2 \cdot 3}$

Rewrite $148$ as $2^{2} \cdot 37$ .

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Factor $4$ out of $148$ .

$x = \frac{2 \pm \sqrt{4 (37)}}{2 \cdot 3}$

Rewrite $4$ as $2^{2}$ .

$x = \frac{2 \pm \sqrt{2^{2} \cdot 37}}{2 \cdot 3}$

Pull terms out from under the radical.

$x = \frac{2 \pm 2 \sqrt{37}}{2 \cdot 3}$

Multiply $2$ by $3$ .

$x = \frac{2 \pm 2 \sqrt{37}}{6}$

Simplify $\frac{2 \pm 2 \sqrt{37}}{6}$ .

$x = \frac{1 \pm \sqrt{37}}{3}$

Change the $\pm$ to $+$ .

$x = \frac{1 + \sqrt{37}}{3}$

Simplify the expression to solve for the $-$ portion of the $\pm$ .

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Simplify the numerator.

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Raise $- 2$ to the power of $2$ .

$x = \frac{2 \pm \sqrt{4 - 4 \cdot (3 \cdot - 12)}}{2 \cdot 3}$

Multiply $3$ by $- 12$ .

$x = \frac{2 \pm \sqrt{4 - 4 \cdot - 36}}{2 \cdot 3}$

Multiply $- 4$ by $- 36$ .

$x = \frac{2 \pm \sqrt{4 + 144}}{2 \cdot 3}$

Add $4$ and $144$ .

$x = \frac{2 \pm \sqrt{148}}{2 \cdot 3}$

Rewrite $148$ as $2^{2} \cdot 37$ .

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Factor $4$ out of $148$ .

$x = \frac{2 \pm \sqrt{4 (37)}}{2 \cdot 3}$

Rewrite $4$ as $2^{2}$ .

$x = \frac{2 \pm \sqrt{2^{2} \cdot 37}}{2 \cdot 3}$

Pull terms out from under the radical.

$x = \frac{2 \pm 2 \sqrt{37}}{2 \cdot 3}$

Multiply $2$ by $3$ .

$x = \frac{2 \pm 2 \sqrt{37}}{6}$

Simplify $\frac{2 \pm 2 \sqrt{37}}{6}$ .

$x = \frac{1 \pm \sqrt{37}}{3}$

Change the $\pm$ to $-$ .

$x = \frac{1 - \sqrt{37}}{3}$

The final answer is the combination of both solutions.

$x = \frac{1 + \sqrt{37}}{3}, \frac{1 - \sqrt{37}}{3}$

The result can be shown in multiple forms.

Exact Form:

$x = \frac{1 + \sqrt{37}}{3}, \frac{1 - \sqrt{37}}{3}$

Decimal Form:

$x = 2.36092084 \dots, - 1.69425417 \dots$

Solve Using the Square Root Property 8x+12=3x^2+6x

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