Solve Using the Square Root Property x^2-160=0

$x^{2} - 160 = 0$

Add $160$ to both sides of the equation.

$x^{2} = 160$

Take the square root of both sides of the equation to eliminate the exponent on the left side.

$x = \pm \sqrt{160}$

The complete solution is the result of both the positive and negative portions of the solution.

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Simplify the right side of the equation.

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Rewrite $160$ as $4^{2} \cdot 10$ .

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Factor $16$ out of $160$ .

$x = \pm \sqrt{16 (10)}$

Rewrite $16$ as $4^{2}$ .

$x = \pm \sqrt{4^{2} \cdot 10}$

Pull terms out from under the radical.

$x = \pm 4 \sqrt{10}$

The complete solution is the result of both the positive and negative portions of the solution.

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First, use the positive value of the $\pm$ to find the first solution.

$x = 4 \sqrt{10}$

Next, use the negative value of the $\pm$ to find the second solution.

$x = - 4 \sqrt{10}$

The complete solution is the result of both the positive and negative portions of the solution.

$x = 4 \sqrt{10}, - 4 \sqrt{10}$

The result can be shown in multiple forms.

Exact Form:

$x = 4 \sqrt{10}, - 4 \sqrt{10}$

Decimal Form:

$x = 12.64911064 \dots, - 12.64911064 \dots$

Solve Using the Square Root Property x^2-160=0

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